Two masses of 1 , kg and 2 , kg respectively | vedclass

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(B) Let the acceleration of the $1 \, kg$ mass be $a_1 = 10 \, m/s^2$ (towards the right).Let the acceleration of the $2 \, kg$ mass be $a_2$.Applying

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$5$

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(B) Let the acceleration of the $1 \, kg$ mass be $a_1 = 10 \, m/s^2$ (towards the right).Let the acceleration of the $2 \, kg$ mass be $a_2$.Applying Newton's second law for the system of two masses connected by a spring,the external force $F_{ext}$ acting on the system is equal to the sum of the products of mass and acceleration of each individual body:$F_{ext} = m_1 a_1 + m_2 a_2$Given $F_{ext} = 20 \, N$,$m_1 = 1 \, kg$,$m_2 = 2 \, kg$,and $a_1 = 10 \, m/s^2$:$20 = (1 	imes 10) + (2 	imes a_2)$$20 = 10 + 2 a_2$$10 = 2 a_2$$a_2 = 5 \, m/s^2$Thus,the acceleration of the $2 \, kg$ mass is $5 \, m/s^2$.

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